Ln(x^2-1)/(x^2+1)

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Solution for Ln(x^2-1)/(x^2+1) equation: 


D( x )

x^2+1 = 0

x^2-1 <= 0

x^2+1 = 0

x^2+1 = 0

1*x^2 = -1 // : 1

x^2 = -1

x^2-1 <= 0

x^2-1 <= 0

1*x^2 <= 1

1*x^2 <= 1 // : 1

x^2 <= 1/1

x^2 <= 1

x^2 <= 1 // ^ 1/2

abs(x) <= 1

x in <-1:1>

x in (-oo:-1) U (1:+oo)

ln(x^2-1)/(x^2+1) = 0

ln(x^2-1)/(x^2+1) = 0 // * x^2+1

ln(x^2-1) = 0

ln(x^2-1) = ln(e^0)

x^2-1 = e^0

x^2-e^0-1 = 0

1*x^2 = 2 // : 1

x^2 = 2

x^2 = 2 // ^ 1/2

abs(x) = 2^(1/2)

x = 2^(1/2) or x = -2^(1/2)

x in { 2^(1/2), -2^(1/2) }

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